Chemistry, 13.02.2020 04:09 blakeley7785

Assuming an ionization efficiency of 53.0 % , how many such photons are needed to ionize 1.00 × 10 16 atoms?

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Answer from: wallacelizzy1

This is an incomplete question, here is a complete question.

The first ionization energy of a carbon atom is 1.81 aJ (attojoules).

Assuming an ionization efficiency of 53.0 %, how many such photons are needed to ionize 1.00 × 10¹⁶ atoms?

Answer : The number of photons needed to ionize 1.00 × 10¹⁶ atoms are, $1.89\times 10^{16}$

Explanation : Given,

Energy = $1.81aJ=1.81\times 10^{-18}J$

First we have to calculate the energy required to ionize the atom.

Energy required to ionize the atom = $53.0\%\times (1.81\times 10^{-18}J0$

Energy required to ionize the atom = $\frac{53.0}{100}\times (1.81\times 10^{-18}J)$

Energy required to ionize the atom = $9.59\times 10^{-19}J$

Now we have to calculate the number of photons are needed to ionize 1.00 × 10¹⁶ atoms.

$\text{Number of photons needed}=\frac{(Energy)\times \text{Number of atoms}}{\text{Available energy}}$

$\text{Number of photons needed}=\frac{(1.81\times 10^{-18})\times (1.00\times 10^{16})}{(9.59\times 10^{-19})}$

$\text{Number of photons needed}=1.89\times 10^{16}$

Thus, the number of photons needed to ionize 1.00 × 10¹⁶ atoms are, $1.89\times 10^{16}$

Answer from: Quest

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

let g(n) be the amount of contaminants (in grams) that remained by the beginning of the nth hour. g is a sequence, what kind of sequence is it, arithmetic or geometric? then, write an explicit formula for the sequence, g(n)=

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

explanation:

Answer from: Quest

The answer would be c. fish

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