3-Chlorocyclopropene, on treatment with AgBF4, gives a precipitate of AgCl and a stable solution of a product that shows a single 1H absorption at 11.04 ppm. What is a likely structure for the product?

check attached picture.

Explanation:

NB: please check attached picture for the drawings.

Chemical shift occurs as a result of shielding and de-shielding which causes the position of the NMR signals to shift. And, the shifts are caused by the involvement of electrons in chemical bonds. Chemical shifts are measured in Hertz that is, cycles per second. The standard compound used for this purpose is tetramethylsilane.

Looking at the question, 3-Chlorocyclopropene is reacted with AgBF4 and it gives precipitate of AgCl and a stable solution of a product. The question now says that the product shows a single 1H absorption at 11.04 ppm.

The Nuclear Magnetic Resonance (NMR) spectroscopy, H'NMR which is 11.04 ppm indicates aromaticity. And one single 1H equal atoms of hydrogen is because of the Resonance effect.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.