Use C1V1 = C2V2 to calculate the molarity of a potassium bromide solution that is prepared by adding 125mL mL of water to 25mL mL of aqueous 2.00 M potassium bromide solution. Assume volumes are additive, and report your answer to three significant figures.

0.4M

Explanation:

This would be much easier if we first analized what was given from the question. This is illustrated below:

C1 = 2M

V1 = 25mL

C2 =?

V2 = 125mL

C1V1 = C2V2

2x25= C2 x 125

Divide both side by 125, we have:

C2 = (2x25) /125

C2 = 0.4M

Therefore, the molarity of potassium bromide formed will be 0.4M

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