Gold is isolated from rocks by reaction with aqueous cyanide, CN:4 Au(s)+8 NaCN(aq)+O 2 (g)+H 2 O(l) longrightarrow 4 Na[Au(CN) 2 ](aq)+4 NaOH(aq) . (a) Which atoms from which compounds are being oxidized, and which at oms from which compounds are being reduced?

Au gets oxidised and Oxygen gets reduced.

Explanation:

4Au(s) + 8NaCN(aq) + O₂(g) + H₂O(l) → 4 Na[Au(CN)₂](aq) + 4 NaOH(aq)

Au is in 0 oxidation state is converted to an compound in that Au is in +2 oxidation state so it gets oxidised.

O₂, gets reduced from 0 to -1 oxidation state, so it also gets reduced.

Na and CN remains as such but with different atoms.

i have no clue hope you find the answer