What amount of pure acid must be added to 600 mL of a 40% acid solution to produce a 60% acid solution?

You need to add 300mL of a pure acid to produce a 60% acid solution.

Explanation:

Pure acid is a 100% acid. If you suppose X is the volume addition of the pure acid it is possible to write:

100%X + 600×40% = (600+X)60% (M₁V₁=M₂V₂)

100X + 24000 = 36000 + 60x

40X = 12000

X = 300

That means you need to add 300mL of a pure acid to produce a 60% acid solution.

I hope it helps!

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

3

explanation: