A metal sphere weighing 15.45 g is added to 21.27 mL of water in a graduated cylinder. The water level rises to 24.78 mL. Calculate the density of the metal. An empty beaker weighs 32.4257 g. A 10-mL pipet sample of an unknown liquid is transferred to the beaker. The beaker weighs 40 1825 g when weighed with the liquid in it. Calculate the density of the unknown liquid.

1. Density of Metal = 4.40g/cm³

2. Density of Liquid = 0.77568g/cm³

Explanation:

1.

Given

Initial Volume of Water = Vi = 21.27mL

Volume of Water = VF = 24.78 mL

Mass of Sphere= 15.45 g

Density = Mass/Volume

Change in Volume = 24.78 - 21.27 = 3.51 mL

Density = 15.45/3.51

Density = 4.40g/ml

1ml = 1cm³

So, density = 4.40/cm³

2.

Initial Mass of Beaker = Mb = 32.4257g

Final Mass of Beaker = Mf = 40.1825 g

V = 10 mL

Density = D = ?

Change in Mass =: MF – MI= 40.1825 – 32.4257 = 7.7568 g

Density = Mass/Volume

Density = 7.7568g/10mL

Density = 0.77568g/mL

1mL = 1cm³

So, density = 0.77568g/cm³

yes it is balanced

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