A high blood alcohol concentration is considered to be 0.25 g/dL. What is the molarity of this blood alcohol (CH3CH2OH) level?

0.054 M

Explanation:

A high blood alcohol concentration is considered to be 0.25 g/dL. We will express it in g/L, considering that 1 L = 10 dL.

0.25 g/dL × (10 dL/1 L) = 2.5 g/L

The molar mass of this blood alcohol (ethanol) is 46.07 g/mol. The molarity of this alcohol (moles of solute per liter of solution) is:

2.5 g/L × (1 mol/46.07 g) = 0.054 mol/L = 0.054 M

thats a little if u want the answer just look it up on google thats what i do haha : )

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2