A solution of bleach has about 1.5 g of NaOCl dissolved in 220 mL of solution. What is the molarity?

0.091 mol/L

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),  

n = moles of solute ( unit = mol ),  

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the data of the question , it is given that ,

w = 1.5 g

V = 220 mL

Since ,

1 mL = 1/1000L

V = 0.220 L

As we known , the mass of bleach NaOCl is ,

m = 74.44 g/mol

from the above equation , moles can be calculated as -

n = w / m

n = 1.5g / 74.44 g/mol

n = 0.0201 mol

Molarity of the solution is calculated as ,

M = n / V

M = 0.0201 mol / 0.220 L

M = 0.091 mol/L

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