Conversion of 0.702 g of liquid water to steam at 100.0°C requires 1.56 kJ of heat. Calculate the molar enthalpy of evaporation of water at 100.0°C.

The molar enthalpy of evaporation of water at 100.0°C is 40 kJ

Explanation:

Calculation of the moles of as:-

Mass = 0.702 g

Molar mass of = 18 g/mol

The formula for the calculation of moles is shown below:

Thus,

Given that:-

It means that when 0.039 moles of water undergoes evaporation, 1.56 kJ of energy is used

Also,

When 1 mole of water undergoes evaporation, of energy is used

The molar enthalpy of evaporation of water at 100.0°C is 40 kJ

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error