Chemistry, 10.02.2020 00:40 angie1129

Getting empirical formula, but they also gave molar mass too.

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Answer from: Kennethabrown09

Empirical formula is PNCl₂

Explanation:

Percent composition means that 100 g of compound has x g of each element.

In 100 g of compound x, we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl.

So, let's make some rules of three:

In 100 g of compound we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl

In 579.43 g of compound we have:

(579.43 . 26.73) / 100 = 155 g of P

(579.43 . 12.09) / 100 = 70 g of N

(579.43 . 61.18) / 100 = 354 g of Cl

Let's convert the mass of the elements in moles.

155 g of P / 30.97 g/mol = 5 P

70 g / 14 g/mol = 5 N

354 g / 35.45 g/mol = 10 Cl

Answer from: JeffTheGoat

The empirical formula has a molar mass of 115.88 g/mol

The molecular formula = P5N5Cl10

Explanation:

Step 1: Data given

Suppose the mass of compound X = 100.0 grams

Compound X contains:

26.73 % phosphorus = 26.73 grams

12.09 % nitrogen = 12.09 grams

61.18 % chlorine = 61.18 grams

Molar mass of phosphorus = 30.97 g/mol

Molar mass of nitrogen = 14.01 g/mol

Molar mass of chlorine = 35.45 g/mol

Step 2: Calculate moles

Mol = mass / molar mass

Mol P = 26.73 grams / 30.97 g/mol

Mol P = 0.8631 moles

Mol N = 12.09 grams / 14.01 g/mol

Mol N = 0.8630 moles

Mol Cl = 61.18 grams / 35.45 g/mol

Mol Cl = 1.726 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

P: 0.8631 moles / 0.8630 = 1

N: 0.8630 moles / 0.8630 moles = 1

Cl: 1.726 / 0.8630 = 2

The empirical formula is PNCl2

The empirical formula has a molar mass of 115.88 g/mol

The compound has a molar mass of 579.43 g/mol

579.43/115.88 = 5

The molecular formula is 5*(PNCl2) = P5N5Cl10

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Answer from: Quest

where are the choice options?

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