The rate constant is 0.556 l mol-1 s-1 at some temperature. if the initial concentration of nobr in the container is 0.32 m, how long will it take for the concentration to decrease to 0.039 m

12.96 seconds

Explanation:

Assuming the reaction follows a first order

Rate = K[NOBr] = change in concentration of NOBr/time

K = 0.556 L mol^-1 s^-1

Change in concentration of NOBr = 0.32M - 0.039M = 0.281M

0.281/t = 0.556×0.039

t = 0.281/0.021684 = 12.96 seconds

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