Calculate the boiling point of a solution prepared by dissolving 70.0 g of naphthalene, c10h8 (a nonvolatile nonelectrolyte), in 220.0 g of benzene, c6h6. the kb for benzene = 2.53oc/m. the boiling point of pure benzene is 80.1oc.. ans: 86.4 degrees celsius. i did this so far. 1)70g c10h8(1mol c10h8/128gc10h8)= .546mol c10h8. benzene)=2.482m. 3) (2.482)(2.53 c/m)=6.289. i'm not sure if i am starting this off right, can anyone me get the correct answer? ans ty!

86.4°C  is the boiling point of a solution.

Explanation:

where,

Mass of benzene = 220.0 g = 0.220 kg

Mass of solute or naphthalene = 70.0 g

=Elevation in boiling point

= Boiling point constant of solvent = 2.53 °C/m(benzene)

1 =  van't Hoff factor  (organic solute)

m = molality

86.4°C  is the boiling point of a solution.

it is called acid bonding

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