How many grams of water will form of 10.54 g h2 react with 95.10 g o2?

2h2 + o2 = 2h2o

The balanced chemical reaction:

2H2 + O2 = 2H2O

We are given the amount of the reactant to be used for this reaction. These values will be the starting point of the calculations. First, we need to fine the limiting reactant.

10.54 g H2 ( 1 mol H2 / 2.02 g H2 ) = 5.22 mol H2
95.10 g O2 ( 1 mol O2 / 32 g H2 ) = 2.97 mol O2

The limiting reactant is the hydrogen gas. We use this value for further calculations.

5.22 mol H2 ( 2 mol H2O / 1 mol H2 ) ( 18.02 g / 1 mol ) = 188.13 g H2O 

Bar graph

It shows that the experiment is designed properly.