2. a 237 g piece of molybdenum, initially at 100.0 °c, was dropped into 244 g of
water at 10.0°c. when the system came to thermal equilibrium, the temperature
was 15.3°c. what is the specific heat capacity of molybdenum? the specific heat
capacity of water is 4.184 j/g. k. (2.5 points)

Explanation:

1. Energy balance

By the first law of thermodynamics, considering the system is closed and isolated, the heat released by the 237 g piece of molybdenum equals the heat absorbed by the 244 g of water.

2. Heat equation

The heat released or absorbed by a substance is proportional to the product of the mass, the specific heat and the change in temperature

Q = m × C × ΔT

3. Heat released by the 237 g piece of molybdenum

At equilibrium:

Q₁ = 237 g × C × (100.0ºC - 15.3ºC)

4. Heat absorbed by the 244 g of water

At equilibrium:

Q₂ = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)

5. Solve for C from Q₁ = Q₂

237 g × C × (100.0ºC - 15.3ºC) = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)20,073.9 × C = 5,410.7488 J/gºCC = 0.2695 J/gºC

The result must be reported with 3 significant figures: C = 0.270 J/gºC.

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic