A0.732 g sample of a compound that might be iron(ii) chloride, nickel(ii) chloride, calcium chloride, or zinc chloride is dissolved in water, and 22.40 ml of 0.515 m agno3 is required to completely precipitate all the chloride ion as silver chloride. what is the compound?

Molar Mass of X = 56 g/mol

56 g/mol is the Molar Mass of iron (Fe), So X is iron (Fe)

Reaction will become:

Explanation:

Consider the reaction:

Volume of =22.40 ml=0.0224 L

concentration of =0.515 M

Moles of =n= Volume of

Moles of =n= 0.224 * 0.515

Moles of =n= 0.011536 mol

1 Mole of reacts with 2 moles of  

Moles of   =

Moles of =0.011536/2

Moles of = 0.05768 mol

Mass of = 0.732 g

Molar Mass of =Mass/Number of moles

Molar Mass of = 0.732/0.05768

Molar Mass of =126.9 g/mol

Now,

Molar Mass of

Molar Mass of = Molar Mass of X + Molar Mass of

126.9=Molar Mass of X + 70.9

Molar Mass of X = 56 g/mol

56 g/mol is the Molar Mass of iron (Fe), So X is iron (Fe)

Reaction will become:

3 1/4 %

explanation: