The solubility product of calcium fluoride (caf2(s); fluorite) is 310-11 at 25c. could a fluoride concentration of 1.0 mg l-1 be obtained in water that contains 200 mg l-1 of calcium?

The given question is incomplete. The complete question is as follows.

The solubility product of calcium fluoride () is  at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?

Explanation:

Reaction equation for the given chemical reaction is as follows.

Therefore, expression for will be as follows.

                     =

Also, moles of  per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]

                =

               =

Hence,    

                       =

                      =  M

Now, moles of  per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]

            =

           =  M

Also,  

                      =

                     =  M

Hence, ionic product =

                 =

                =

As, the ionic product is less than the , this means that the fluoride will be soluble in water containing the calcium.

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