Propose a plausible two-step mechanism for the reaction given below with the steps provided. a+2b → c + e (slow) d + b → e (fast) 28 → c + e (slow) a + e → d (fast) a+b→c+d(slow) a+b→c+e(slow) a+b→c+e(fast) a+b→c+d(fast) d→c+e(fast) overall reaction: a+2b → c + e experimentally determined rate law rate = ma]

Radon-222 or rn-222 has a half-life of 3.82 days. to determine the fraction of an original sample of rn-222 that remains unchanged after 7.646 days, we calculate the amount of rn-222 remaining after 7.646 days and divide it with the original amount. using 1 gram as a basis and using half-life calculation methods, we can determine that  0.249 or 0.25  grams of rn-222 will remain, and thus the fraction remaining is 0.25 or 1/4.

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V=s/t  4.5 = 5000+15000+20000+5000t=45000/4.5t=10000sto convert divide by 360answer is 3 hours