Chemistry, 27.01.2020 19:31 wolfking800

Which has more thermal energy, a 75g metal pot or 75g of water that are both 79* celsius

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Answer from: hillarytrinh

75 g of water

Explanation:

Thermal energy refers to an object's internal energy. This internal energy is brought about by kinetic energy (energy due to motion). If two objects have the same mass, their thermal energy can be drawn upon the presence of varying temperatures. However, in the case above, both water and metal pot have the same mass and temperatures. Thus, we have to compare both of them in terms of "specific heat" (not on the basis of temperature).

Specific heat is a form of thermal energy. It refers to the object's resistance when there is a change in temperature. Water is said to have more specific heat than metals. In fact, is has a "high specific heat." This means that once the water is heated, it takes a longer time for it to cool down compared to metals. This is because its heat loss is in a slower process.

Thus, a 75 g of water has more thermal energy than a 75 g of metal pot.

Answer from: Quest

the answer is yes

it has kinetic energy

reason

an object has kinetic energy when you stop the force carrying it, the object will stay in motion.

hope this contact me for more questions if you'd like: )

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

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Which has more thermal energy, a 75g metal pot or 75g of water that are both 79* celsius...