Chemistry, 27.01.2020 05:31 rqg001e

what is the pressure (in torr) inside a 4.0 liter flask at 24°c of 7.2 grams of nitrogen gas (remember that nitrogen gas is diatomic)?

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Answer from: mya1318

1190.2 Torr

Explanation:

Data Given:

Volume of a nitrogen gas ( V )= 4.0 L

temperature of a gas ( T ) = 24 °C

Convert °C to K

T = °C + 273

T = 24 + 273 = 297 K

mass of nitrogen gas (m) = 7.2 g

Pressure of a gas ( P ) =? in Torr

Solution:

Formula to be used

PV= nRT . . . . . . .(1)

As we Know

n= m/M

So, the equation 1 can be written as

PV = (m/M)RT

Rearrange the above formula

P = (m/M)RT / V . . . . . . . . . . (2)

Where

R is ideal gas constant

R = 62.37 L Torr mol⁻¹ K⁻¹

M = molar mass of N₂

molar mass of N₂ = 2(14) = 28 g/mol

m = mass of N₂ gas

Put values in equation 1

P = (m/M)RT / V

P = (7.2 g / 28 g/mol) 62.37 L Torr mol⁻¹ K⁻¹ x 297 K / 4.0 L

P = 0.257 mol x 62.37 L Torr mol⁻¹ K⁻¹ x 297 K /4.0 L

P = 4761 L Torr / 4.0 L

P = 1190.2 Torr

Pressure of gas (N₂) = 1190.2 Torr

Answer from: Quest

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.

for example, fusion of hydrogen atoms at the sun.

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.

Answer from: Quest

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is 2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that 10 dm = 1 m ⇔ 10³ dm³ = 1 m³then we use the fact that 10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting: $\dfrac{\text{2 mol}}{\text{dm}^{3}} \cdot \dfrac{\text{10}^3\text{ dm}^3}{\text{1 m}^3} \cdot \dfrac{\text{1 m}^3}{10^6\text{ cm}^3} \\ \\ = \dfrac{\text{2 mol}}{1} \cdot \dfrac{\text{10}^3}{1} \cdot \dfrac{1}{10^6\text{ cm}^3} \qquad \text{\footnotesize cancelling units} \\ \\ = \dfrac{2\text{ mol}}{10^3 \text{ cm}^3} \\ \\ = 0.002\text{ mol/cm}^3$ now we have to find the moles of hydrochloric acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by molar mass = (mass ca) + (mass c) + 3(mass o) = 40 + 12 + 3(16) = 100 g/molconvert the given 5 g to moles: mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃) = 0.05 mol hcl * 2 = 0.1 mol hcl we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get volume = moles / concentration volume = 0.1 mol / (0.002 mol/cm³) volume = 50 cm³

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what is the pressure (in torr) inside a 4.0 liter flask at 24°c of 7.2 grams of nitrogen gas (rememb...

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