How many moles of compound are present in 33 grams of kmno4?
answer in units of mol.

0.21 mole

Explanation:

Atomic mass of Potassium, K = 39.1g/mol

Atomic mass of Manganese, Mn = 54.9g/mol

Atomic mass of Oxygen, I = 16g/mol

First find the molar mass of KMnO4, that is

KMnO4 = 39.1+54.9+(16)4

Molar mass of KMnO4 = 158g/mol

Hence,

1 mole of KMnO4 = 158g

Let x mole of KMnO4 = 33g

x = 33/158 mole

x = 0.21 mole

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.