6.755 mol pb(so4)2
how many atoms

4.07x 10²⁴ atoms Pb( SO4)2

Explanation: Solution:

6.755 moles Pb(SO4)2 x 6.022x10²³ atoms Pb(SO4)2 / 1 mole Pb(SO4)2

= 4.07x10²⁴ atoms Pb(SO4)2

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o