:a certain liquid has a vapor pressure of 6.91 mmhg at 0 °c. if this liquid has a normal boiling point of 105 °c, what is the liquid's heat of vaporization in kj/mol?

liquid's heat of vaporization = 38.4 kJ/mol

Explanation:

given data

vapor pressure P1 = 6.91 mmHg

at temperature = 0 °C = 273.15 K

boiling temperature = 105 °C

solution

for vapor pressure and temperature we get here

P2 = 760.0 mmHg

T2 = 68.73°C = 378.15 K

we use here the Clausius-Clapeyron Equation that is

ln =     .................1

put here value

In

solve it we get

x = 38445 J/mol

liquid's heat of vaporization = 38.4 kJ/mol

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

they are all solids.