In one compound of nitrogen and oxygen, 0.615 grams of nitrogen combines with 0.703 grams of oxygen. in another 1.27 grams of nitrogen combines with 2.90 grams of oxygen. show how these data illustrate the law of multiple proportions.

Answer in explanation

Explanation:

In the first case, we divide each of the masses by the respective atomic masses:

N =0.615/14 = 0.043928571428571

O = 0.703/16 = 0.0439375

It can be seen here that the values are similar, hence the formula is NO

now let us look at the second data set:

N = 1.27/14 = 0.090714285714286

O = 2.9/16 = 0.18125

We now divide by the smallest

N = 090714285714286/090714285714286 = 1

O = 0.18125/090714285714286 = 2

The formula here is thus NO2.

It can be seen that there are different oxides of nitrogen here which clearly indicates the law of multiple proportion.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

the volume increases