How many molecules of propane (c3h8) are in 5.9 moles of propane?

3.55 x 10²⁴ molecules

Explanation:

Data Given:

moles of propane = 5.9 moles

molecules of propane (C₈H₈) = ?

Solution

Formula will be used

         no. of moles = no. of molecules / Avogadro's number

Rearrange the above equation:

         no. of molecules = no. of moles x Avogadro's number . . . . .  (1)

Where

Avogadro's number = 6.022 x 10²³

Put values in equation 1

         no. of molecules =5.9 mol x 6.022 x 10²³ (molecules/mol)

         no. of molecules = 3.55 x 10²⁴ molecules

So,

There are 3.55 x 10²⁴molecules in 5.9 moles of propane

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3