You have 1.00g of two metals a& b. the specific heat of metal a is 0.568j/g• °c and metal b is 1.34j/g•°c both are heated to a temp. of 80°c . which will heat up fastest

Metal A will heat up faster

Explanation:

Step 1: Data given

Mass of the 2 metals = 1.00 grams

The specific heat of metal A is 0.568j/g* °c

The specific heat of metal B is 1.34j/g*°c

Initial temperature = 80 °C

Step 2: Calculate energy needed

A high specific heat value means that it takes MORE energy to raise (or lower) its temperature.

A low value means that it does not take very much energy to heat or cool it.

Step 3: Calculate energy needed to raise 1 °C

Q = m*c*ΔT

Metal A:   Q = 1.00g * 0.568 J/g°C * 1°C

  Q = 0.568 J

Metal B    Q = 1.00g * 1.34 J/g°C * 1°C

  Q = 1.34 J

We need 0.568 Joules energy to raise the temperature with 1°C for metal A.

We need 1.34 Joules energy to raise the temperature with 1°C for metal B.

Since we need less energy to raise the temperature for metal A, it will heat up faster.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.