The strongest intermolecular interactions between hydrogen fluoride (hf) molecules arise from a) dipole dipole forces b) hydrogen bonding c) ion dipole interactions d) ionic bondse) london dispersion forces

The answers are: A) dipole-dipole forces and B) hydrogen bonding

Explanation:

Hydrogen bonds are a class of bond that form from the attraction between a hydrogen atom and an atom that has a negative charge. This attraction is known by the name of dipole-dipole interaction.

In this case, since the hydrogen atom has a low electronegativity and since the fluorine atom has a high electronegativity, therefore, between them there will be a positive charge on the hydrogen atom and a negative charge on the fluorine atom. . In this way, they will have hydrogen bonds between the hydrogen atom and the fluorine atom.

The attached figure shows the bonds.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.