For a certain chemical reaction, the standard gibbs free energy of reaction is 144. kj. calculate the temperature at which the equilibrium constant k = 5.9 × 10 . round your answer to the nearest degree.

The question is incomplete, the complete question is:

For a certain chemical reaction, the standard Gibbs free energy of reaction is 144. kJ. Calculate the temperature at which the equilibrium constant K = .

Round your answer to the nearest degree.

25°C is the temperature at which the equilibrium constant is .

Explanation:

where,

= standard Gibbs free energy = 144.0 kJ=144,000 J  (Conversion factor: 1kJ = 1000J)

R = Gas constant =

T = temperature at which reaction is occurring = ?

K = Equilibrium constant of the reaction =

Putting values in above equation, we get:

T = 298.15 K

T = 298.15 - 273 °C = 25°C

25°C is the temperature at which the equilibrium constant is .

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".