Match the following aqueous solutions with the appropriate letter from the column on the right. 1. 0.11 m febr3 a. highest boiling point 2. 0.15 m cubr2 b. second highest boiling point 3. 0.24 m agno3 c. third highest boiling point d 4. 0.51 m glucose(nonelectrolyte) d. lowest boiling point

1. For 0.11 m  : Lowest boiling point

2. For 0.15

: Second highest boiling point

3. For 0.24

: Third highest boiling point

4.  0.51 m glucose : Highest boiling point

Explanation:

Elevation in boiling point:

where,

= change in boiling point

i= vant hoff factor

= boiling point constant

m = molality

1. For 0.11 m

, i= 4 as it is a electrolyte and dissociate to give 4 ions and concentration of ions will be

2. For 0.15

, i= 3 as it is a electrolyte and dissociate to give 3 ions, concentration of ions will be

3. For 0.24

, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be

4. 0.51 m glucose

i= 1 as it is a non electrolyte and does not dissociate to give ions, concentration will be

Thus as boiling point depends on the concentration of solutes, the solution having highest concentration will have highest boiling point.

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.