The two naturally occurring isotopes of bromine are

81br (80.916 amu, 49.31%) and

79br (78.918 amu, 50.69%).

the two naturally occurring isotopes of chlorine are

37cl (36.966 amu, 24.23%) and

35cl (34.969 amu, 75.77%).

bromine and chlorine combine to form bromine monochloride, brcl.

what are the masses of the four different brcl molecules? express the masses in atomic mass units using six significant figures, in decreasing numeric order (highest to lowest), separated by commas.

The decreasing order of masses of for different BrCl molecules :

=

=

Explanation:

The two naturally occurring isotopes of bromine are

81-Br (80.916 amu, 49.31%)   79-Br (78.918 amu, 50.69%).

The two naturally occurring isotopes of chlorine are

37-Cl (36.966 amu, 24.23%) and   35- Cl (34.969 amu, 75.77%).

Molar mass of BrCl molecule composed of  81-Br and  37-Cl.

Mass of 81-Br = 80.916 amu

Mass of  37-Cl = 36.966 amu

Molar mass of this BrCl molecule, = 80.916 amu + 36.966 amu

= 117.882 amu

Molar mass of BrCl molecule composed of  79-Br and  35-Cl.

Mass of 79-Br = 78.918 amu

Mass of  35-Cl = 34.969 amu

Molar mass of this BrCl  molecule = 78.918 amu + 34.969 amu

= 113.887 amu

Molar mass of BrCl molecule composed of  81-Br and  35-Cl.

Mass of 81-Br = 80.916 amu

Mass of  35-Cl = 34.969 amu

Molar mass of this BrCl molecule, = 80.916 amu + 34.969 amu

= 115.885 amu

Molar mass of BrCl molecule composed of  79-Br and  37-Cl.

Mass of 79-Br = 78.918 amu

Mass of  37-Cl = 36.966 amu

Molar mass of this BrCl molecule, = 78.918 amu + 36.966 amu

= 115.884 amu

The decreasing order of masses of for different BrCl molecules :

=

=

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.