In a closed container, the vapor pressure of 10 ml of ethanol at 20 degrees c is 5.85 kpa. what is the vapor pressure of 20 ml of ethanol at the same temperature?

Explanation:

At same temperature and same number of moles, Using Boyle's law  

Given ,  

V₁ = 10 mL

V₂ = 20 mL

P₁ = 5.85 kPa

P₂ = ?

Using above equation as:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.