Asample of 37ar undergoes 8540 disintegrations/min initially but undergoes 6990 disintegrations/min after 10.0 days. what is the half-life of 37ar in days?

Explanation:

Expression for rate constant and half-life is as follows.

            k =

The given data is as follows.

         a = 8540 disintegrations/min

and,   (a - x) = 6990 disintegrations/min

Putting the given values into the above formula as follows.

       k =

           = 0.02

Now, we will calculate the half-life as follows.

      Half-life =

                   = 34.6 days

Thus, we can conclude that the half-life of 37Ar in days is 34.6 days.

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explanation:

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6