Asolution is made by mixing of methanol and of acetic acid . calculate the mole fraction of methanol in this solution. round your answer to significant digits.

The question is incomplete, here is the complete question:

A solution is made by mixing 146. g of methanol and 72. g of acetic acid . Calculate the mole fraction of methanol in this solution. Round your answer to 2 significant digits.

The mole fraction of methanol is 0.79 and that of acetic acid is 0.21

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of methanol = 146. g

Molar mass of methanol = 32 g/mol

Putting values in equation 1, we get:

Given mass of acetic acid = 72. g

Molar mass of acetic acid = 60 g/mol

Putting values in equation 1, we get:

Mole fraction of a substance is given by:

For methanol:

For methanol:

Hence, the mole fraction of methanol is 0.79 and that of acetic acid is 0.21

the correct answer is:

a. formation of precipitation

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