To calculate the enthalpy change for the reaction, 2co (g) + o2 (g) imported asset 2 co2 (g), you can use δhf0 values for each reactant and product. which setup shows how the enthalpy change should be calculated?

δh0reaction = [δhf0 co2(g)] + [δhf0 co(g) - δhf0 o2(g)]

δh0reaction = [δhf0 co2(g)] - [δhf0 co(g) + δhf0 o2(g)]

δh0reaction = [δhf0 co(g) + δhf0 o2(g)] - [δhf0 co2(g)]

δh0reaction = [δhf0 co(g) - δhf0 o2(g)] + [δhf0 co2(g)]

ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]

Explanation:

Chemical equation:

CO + O₂   →  CO₂

Balanced chemical equation:

2CO + O₂   →  2CO₂

The standard enthalpy for the formation of CO = -110.5 kj/mol

The standard enthalpy for the formation of O₂  = 0  kj/mol

The standard enthalpy for the formation of CO₂  = -393.5 kj/mol

Now we will put the values in equation:

ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]

ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]

ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]

ΔH0reaction = -283 kj/mol

pure water does not conduct electricity very well. however, when certain substances are dissolved in water, the solution does conduct electricity. you can make a simple device that shows how well a solution conducts electricity. this device uses a flashlight bulb to indicate how well the solution conducts electricity. the better the solution conducts electricity, the brighter the bulb will glow.

explanation: