31.65 ml volume of 1.07 m fe(no3)3 is mixed with 44.96 ml of 0.79m fe(no3)3 solution. calculate the molar concentration of the final solution. save rounding until the end.

[Fe(NO₃)₃] = 0.90 M

Explanation:

Molarity = Mol/L

Total volume of solution: 31.65 mL + 44.96 mL = 76.61 mL

Let's determine the moles of salt ([M] . volume)

0.03165 L  . 1.07M = 0.0338 moles

0.04496L .  0.79M = 0.0355 moles

Total moles Fe(NO₃)₃ = 0.0338 + 0.0355 = 0.0693 moles

Volume of solution = 76.61 mL = 0.07661 L

0.0693 mol / 0.07661 L = 0.90 mol/L

The molar concentration of the final solution is 0.9057 M

Explanation:

Step 1: Data given

Volume of a 1.07 M Fe(NO3)3 solution = 31.65 mL = 0.03165 L

Volume of a 0.79 M Fe(NO3)3 solution = 44.96 mL = 0.04496 L

Step 2: Calculate moles of 1.07 M Fe(NO3)3 solution

Moles = molarity * volume

Moles = 1.07 M * 0.03165 L

Moles = 0.0338655 moles

Step 3: Calculate moles of 0.79 M Fe(NO3)3 solution

Moles = 0.79 M * 0.04496 L

Moles = 0.0355184 moles

Step 4: Calculate total moles

Total moles = 0.0339 + 0.0355

Total moles = 0.0693839 moles

Step 5: Calculate total volume

Total volume = 31.65 mL + 44.96 mL

Total volume = 76.61 mL = 0.07661 L

Step 6: Calculate molar concentration of the final solution

Concentration = moles / volume

Concentration = 0.0693839 moles / 0.07661 L

Concentration = 0.9057 M

The molar concentration of the final solution is 0.9057 M

i believe it is c.) 1575 j.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.