Amixture of methanol (mw = 32.04 g/mol) and ethanol (mw = 46.07 g/mol) has an average molecular weight of 43.01 g/mol. what is the mol fraction of methanol in this mixture?

The mol fraction of methanol is 0.2181

Explanation:

Step 1: Data given

Molar mass of methanol = 32.04 g/mol

Molar mass of ethanol = 46.07 g/mol

Average molecular weight = 43.01 g/mol

Step 2: Calculate the mol fraction of methanol

Mol fraction = number of moles / total number of moles

We know that mol fraction of methanol + mol fraction of ethanol = 1

Mol fraction methanol = 1 - mol fraction of ethanol

X = 1-Y

Let's consider methanol = X   and ethanol = Y

32.04*X + 46.07*Y = 43.01

32.04*(1-Y) +46.07Y = 43.01

32.04 - 32.04Y + 46.07Y = 43.01

14.03 Y = 10.97

Y = 0.7819

The mol fraction of ethanol is 0.7819

The mol fraction of methanol is 1 - 0.7819 = 0.2181

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be