An aerosol can filled with propane gas occupies a volume of 250 ml at 23 c and 1.54 atm. if the conditions are changed to stp, what is the new volume in the can?

The new volume is 388 mL

Explanation:

Step 1: Data given

Volume = 250 mL = 0.250 L

Temperature = 23 °C = 296 Kelvin

Pressure = 1.54 atm

Step 2: Calculate number of moles

p*V =n*R*T

n = (p*V)/(R*T)

⇒ n = the number of moles = ?

⇒ V = the volume: the gas occupies = 0.250 L

⇒ The pressure of propane gas = 1.54 atm

⇒ Temperature = 23.0 °C = 296 Kelvin

 ⇒ R = The gas constant = 0.08206 L*atm/K*mol

n = (1.54 * 0.205 ) / ( 0.08206 * 296 )

n = 0.013 moles

Step 3: Calculate new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure =  1.54 atm

⇒ with V1 = the initial volume = 0.250 L

⇒ with T1 = the initial temperature = 296 K

⇒ with P2 = 1.00 atm

⇒ with V2 = The new volume at STP

⇒ with T2 = 298 Kelvin

(1.54*0.250)/296 = (1.00 * V2)/298

V = 0.388 L = 388 mL

The new volume is 388 mL

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.