Study this chemical reaction: pb + 2cl2 = pbcl4then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction. oxidation: :

Oxidation: Pb → Pb⁴⁺ + 4 e⁻

Reduction: 2 Cl₂ + 4 e⁻ → 4 Cl⁻

Explanation:

Let's consider the following redox reaction.

Pb + 2 Cl₂ ⇄ PbCl₄

We can identify both half-reactions.

Oxidation: Pb → Pb⁴⁺ + 4 e⁻

Reduction: 2 Cl₂ + 4 e⁻ → 4 Cl⁻

Pb is oxidized and its oxidation number increases from 0 to 4+ while Cl₂ is reduced and its oxidation number decreases from 0 to 1-.

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