Can i get with this,
the enclosed cabin of a submarine has a volume of 2.4 × 105 liters, a temperature of 312 k, and a pressure of 116 kpa. as people in the cabin breathe, carbon dioxide gas, co2(g), can build up to unsafe levels. air in the cabin becomes unsafe to breathe when the mass of co2(g) in this cabin exceeds 2156 grams. show a numerical setup for calculating the pressure in the submarine cabin if the cabin temperature changes to 293 k.
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Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

Explanation:

Pressure in the submarine = 108.9 kPa

Volume, V = 2.4 * 10^5 L

Pressure, P = 116k Pa

Temperature, T = 312 K

Ideal gas law: PV = nRT  or  n = PV / RT

So, moles of gas, n =116 KPa * 2.4 * 10 ^5L / 8.314 LK Pa K^-1 *312 K

= 1.073 *10^4 mol

when temperature is changed to 293K,

PV = nRT  or P = nRT / V

=1.073 *10^4 mol *8.314 LK Pa mol^-1 K^-1 *293 K / 2.4*10^5L

=108.9 K Pa

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter