What is the limiting reactant in the reaction 3cucl2+2al-> 3cu+2alcl3
3cucl2-2.50g (measured mass),134.45g/mol
2al-.5g(measured mass), 26.98g/mol

The balanced chemical reaction:

3CuCl2+2Al->3Cu+2AlCl3

We are given the amount of the reactant to be used for this reaction. These values will be the starting point of the calculations.

2.50 g CuCl2 ( 1 mol CuCl2 / 134.45 g CuCl2) = 0.019 mol CuCl2
5 g Al ( 1 mol Al / 26.98 g Al ) = 0.185 mol Al

The mole ratio of the reactants is 3:2. In every 3 moles of CuCl2, 2 mol of Al is required. Therefore, the limiting reactant is CuCl2.

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