Which steps are followed to calculate the mass of oxygen (o2) that will react completely with 48.0 grams of aluminum (al)?

- First of all, think the reaction:

4Al  +  3O₂  →  2Al₂O₃

- Afterwards, determine the ratio of reactants  (4:3)

4Al  +  3O₂  →  2Al₂O₃

- Convert the mass of Al into moles, by dividing mass / molar mass

48 g / 26.98 g/m = 1.78 mol

- Make a rule of three to determine the moles of O₂

4 mol of Aluminum react with 3 mol of oxygen, so

1.78 mol of Al, will react with (1.78  . 3) / 4 = 1.33 mol of O₂

- Finally, convert the moles in mass like this:

Mol  . molar mass = mass → 1.33 mol . 32 g/m = 42.7 grams

Explanation:

Reaction

4Al  +  3O₂  →  2Al₂O₃

po-215 i got it right on the quiz

2b2t

explanation:

2b2t