Chemistry, 14.01.2020 22:31 rosaa7

Which will conduct electricity: a solution of water and (nh₄)₂s or a solution of water and c₆h₁₂o₆?

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Answer from: anitadefrances

A solution of water and (NH₄)₂S

Explanation:

In a solution , the electricity can pass from it , if there is presence of free ions , as they are mobile and helps to conduct the electricity .

Therefore , the present of free ions is necessary for a solution to conduct electricity.

Hence, from the given options ,

Solution of water and (NH₄)₂S will conduct electricity as (NH₄)₂S will dissociate completely to the respective ions as they are dissolved in water , and the ions will help to conduct electricity.

Whereas ,

Solution of water and C₆H₁₂O₆ will not conduct electricity , as C₆H₁₂O₆ in water will not dissociate completely , and does not produce ions , hence , won't conduct electricity.

Answer from: Quest

1.consider the following balanced equation and answer parts a through. show calculations for each part.

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.

explanation:

Answer from: Quest

explanation:

i think option no d is the correct answer

40 points and brainliest to anyone who can answer these

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