Write a balanced equation of reaction. solid potassium chlorate is heated to form solid potassium chloride and oxygen gas. express your answer as a chemical equation. identify all of the phases in your answer.

2KClO3(s) → 2KCl(s) + 3O2(g)

Explanation:

Step 1: Data given

Solid potassium chlorate = KClO3(s)

solid potassium chloride = KCl

oxygen gas = O2

Step 2: The balanced equation

KClO3(s) → KCl + O2

On the left side we have 3x O, on the right side we have 2x O

To balance the amount of O we have to multiply KClO3 (on the left side) by 2 and multiply O2 on the right side by 3

2KClO3(s) → KCl(s) + 3O2(g)

On the left we have 2x K, on the right we have 1x K.

To balanced the amount of K we have to multiply KCl on the right side by 2

Now the equation is balanced

2KClO3(s) → 2KCl(s) + 3O2(g)

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

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