Find the molarity and molality of 37.0 wt% hcl. assume the density of the acid is 1.19g/ml

a) M HCl = 32.162 mol/L

b) m HCl = 15.873 mol/Kg

Explanation:

∴ MW HCl = 36.46 g/mol

assuming mass sln = 1 g

∴ mass sln = 1 g = g solvent + g solute

∴ solute: HCl

⇒ 0.37 = g HCl / g sln

⇒ g HCl = 0.37 g

⇒ g ste = 1 - 0.37 = 0.63 g

⇒ Kg ste = (0.63 g)×(Kg/1000 g) = 6.3 E-4 Kg

⇒ mol HCl = (0.37 g HCl)×(mol/36.46 g HCl) = 0.010 mol HCl

∴ V sln = (0.37 g)/(1.19 g/mL) = 0.3109 mL

⇒ V sln = (0.31 mL)×( L/1000 mL) = 3.109 E-4 L

a) molarity (M):

⇒ M HCl = 0.010 mol HCl / 3.109 E-4 L

⇒ M HCl = 32.162 mol/L

b) molality (m):

⇒ m HCl = ( 0.010 mol HCl) / (6.3 E-4 Kg)

⇒ m HCl = 15.873 mol/Kg

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole