A7.028 gram sample of a sodium sulfate hydrate is heated. after driving off all the water, 3.100 grams of the anhydrous salt is left. what is the name of the hydrate?

Explanation:

Given that:-

Mass of the hydrated salt = 7.028 g

Mass of the anhydrous salt = 3.100 g

Mass of water eliminated = Mass of the hydrated salt - Mass of the anhydrous salt = 7.028 - 3.100 g = 3.928 g

Moles of water:

Mass of water = 3.928 g

Molar mass of = 18 g/mol

The formula for the calculation of moles is shown below:

Thus, moles are:

Moles of anhydrous salt:

Amount = 3.100 g

Molar mass of = 142.04 g/mol

Thus, moles are:

The simplest ratio of the two are:

=0.02182 :  0.2212 = 1 : 10

Hence, the formula for hydrate is:-

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.