15.00 ml of a .127 m cacl2 solution are mixed
with25.60 ml of a .137 m
ca(no3)2 solution. what is the
molarconcentration ion in the resulting solution?

The question is incomplete, here is the complete question:

15.00 mL of a 0.127 M solution are mixed  with 25.60 mL of a 0.137 M solution. What is the molar concentration of ions in the resulting solution?

The concentration of calcium and chloride ions in the resulting solution are 0.133 M and 0.266 M respectively.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

where,

are the molarity and volume of the first solution

are the molarity and volume of the second solution

We are given:

Putting all the values in above equation, we get:

The chemical equation for the ionization of calcium chloride follows:

1 mole of calcium chloride produces 1 mole of calcium ions and 2 moles of chloride ions

So, concentration of calcium ion = 0.133 M

Concentration of chloride ions =

Hence, the concentration of calcium and chloride ions in the resulting solution are 0.133 M and 0.266 M respectively.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

the answer is c

tell me if wrong