40 ml of 2.0 molar naoh reacts with 8.0 ml of a
monoproticacid. what is the molarity of the acid?

10 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 8.0 mL

M₂ = 2.0 M

V₂ = 40 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 8.0mL = 2.0 M * 40mL

M₁ = 10 M

Hence, the molarity of the acid = 10 M

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.