A30.84ml volume of 0.128m naoh is required to reach
thephenolphthalein endpoint in the titration of a 5.441g sample
ofvinegar. calculate the percent acetic acid in the vinegar.

Percent acetic acid in the vinegar is 4.35%.

Explanation:

Moles of NaOH = n

Volume of NaOH solution = 30.84 mL = 0.03084 L

Molarity of the NaOH  = 0.128 M

According to reaction ,1 mole of NaOH reacts with 1 mol of acetic acid.

Then ,0.03948 mol of NaIOH will recat with:

of acetic acid.

Mass of 0.03948 moles of acetic acid = 0.003948 mol × 60 g/mol = 0.2368 g

Mass of vinegar solution = 5.441 g

Percent acetic acid in the vinegar :

neutrons are in the middle of the atom and the electrons, which are much smaller.

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