Suppose you add 100 grams of water at 60.0 degrees c to 100
gramsice at 0.00 degrees c. some of the ice melts and cools thewarm
water to 0.00 degrees c. when the ice/water mixture hascome to a
uniform temperature of 0.00 degrees c, how much ice
hasmelted?

The amount of ice melted is 50.3 grams.

Explanation:

To calculate the heat released by water, we use the equation:

where,

q = heat released

m = mass of water = 100 g

c = specific heat capacity of water = 4.186 J/g.°C

= change in temperature =

Putting values in above equation, we get:

The amount of heat released by water will be absorbed by ice.

So, amount of heat absorbed by ice = -q = -(-16744) J = 16744 J

To calculate the enthalpy change of the reaction, we use the equation:

where,

= amount of heat absorbed = 16744 J

m = mass of ice melted = ?

= heat of fusion = 333 J/g

Putting values in above equation, we get:

Hence, the amount of ice melted will be 50.3 g