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the reaction below shows the combustion of butane (c4h10). why is the mole ratio (8 moles co2/2 mol c4h10) used to determine the amount of carbon dioxide (co2) produced when butane (c4h10) combusts in excess oxygen? (1 point)
c4h10 + o2 yields co2 + h2o + heat
butane has a mass that is 4 times greater than co2, so only 2 moles of c4h10 are needed to produce 8 moles of co2.
carbon dioxide has a volume of about one-quarter that of c4h10, so 4 moles of co2 are needed to react with each mole of c4h10.
during combustion, co2 is approximately 4 times more reactive than c4h10, so less c4h10 will participate in the reaction.
when the chemical equation for butane combustion is balanced, 2 moles of c4h10 are needed to produce 8 moles of co2.
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Iwill mark you as brainiest, me
the reaction below shows the combustion of butane (c4h...
the reaction below shows the combustion of butane (c4h...
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