Atire at 21°c has a pressure of 0.82 atm. its temperature decreases to –3.5°c. if there is no volume change in the tire, what is the pressure after the temperature change?

Using ideal gas equation, PV = nRT, and since there is no volume change and amount change, the equation is now P = kT, where k =nR/V. Temperature must be in kelvin From the given, k = (0.82)/ (21 + 273) = 2.78 x 10^-3 Substituting T = -3.5+273, P = 0.75 atm

Density and pressure